a. 2/2+√3
b. 2√5/√5-√2
Penjelasan dengan langkah-langkah:
[tex] = \frac{2}{2 + \sqrt{3} } \times \frac{2 - \sqrt{3} }{2 - \sqrt{3} } [/tex]
[tex] = \frac{2.(2 - \sqrt{3} )}{ {2}^{2} - \sqrt{ {3}^{2} } } [/tex]
[tex] = \frac{4 - 2 \sqrt{3} }{4 - 3} [/tex]
[tex] = \frac{4 - 2 \sqrt{3} }{1} [/tex]
[tex] = 4 - 2 \sqrt{3} [/tex]
[tex] \: [/tex]
[tex] = \frac{2 \sqrt{5} }{ \sqrt{5} - \sqrt{2} } \times \frac{ \sqrt{5} + \sqrt{2} }{ \sqrt{5} + \sqrt{2} } [/tex]
[tex] = \frac{2 \sqrt{5}( \sqrt{5} + \sqrt{2} ) }{ \sqrt{ {5}^{2} } - \sqrt{ {2}^{2} } } [/tex]
[tex] = \frac{2 \sqrt{ {5}^{2} } + 2 \sqrt{5.2} }{5 - 2} [/tex]
[tex] = \frac{10 + 2 \sqrt{10} }{3} [/tex]
semogaaaaaaaaaaaaaaaaa
eh dtmbh ya
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